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From: alopez-o@neumann.uwaterloo.ca (Alex Lopez-Ortiz)
Newsgroups: sci.math,news.answers,sci.answers
Subject: sci.math FAQ: Surface of Sphere
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Date: 17 Feb 2000 22:55:54 GMT
Organization: University of Waterloo
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Archive-name: sci-math-faq/surfaceareaofsphere
Last-modified: February 20, 1998
Version: 7.5
Formula for the Surface Area of a sphere in Euclidean N-Space
This is equivalent to the volume of the N-1 solid which comprises the
boundary of an N-Sphere.
The volume of a ball is the easiest formula to remember: It's r^N
(pi^(N/2))/((N/2)!). The only hard part is taking the factorial of a
half-integer. The real definition is that x! = Gamma (x + 1), but if
you want a formula, it's:
(1/2 + n)! = sqrt(pi) ((2n + 2)!)/((n + 1)!4^(n + 1))
To get the surface area, you just differentiate to get N
(pi^(N/2))/((N/2)!)r^(N - 1).
There is a clever way to obtain this formula using Gaussian integrals.
First, we note that the integral over the line of e^(-x^2) is
sqrt(pi). Therefore the integral over N-space of e^(-x_1^2 - x_2^2 -
... - x_N^2) is sqrt(pi)^n. Now we change to spherical coordinates. We
get the integral from 0 to infinity of Vr^(N - 1)e^(-r^2), where V is
the surface volume of a sphere. Integrate by parts repeatedly to get
the desired formula.
It is possible to derive the volume of the sphere from ``first
principles''.
_________________________________________________________________
--
Alex Lopez-Ortiz alopez-o@unb.ca
http://www.cs.unb.ca/~alopez-o Assistant Professor
Faculty of Computer Science University of New Brunswick